思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
This is better in that there is far less boilerplate, but it doesn't solve everything. Async iteration was retrofitted onto an API that wasn't designed for it, and it shows. Features like BYOB (bring your own buffer) reads aren't accessible through iteration. The underlying complexity of readers, locks, and controllers are still there, just hidden. When something does go wrong, or when additional features of the API are needed, developers find themselves back in the weeds of the original API, trying to understand why their stream is "locked" or why releaseLock() didn't do what they expected or hunting down bottlenecks in code they don't control.
，详情可参考91视频
为基层减负赋能，强调“要明确权责，不能什么事都压给基层，基层该承担哪些工作，要把职责事项搞清楚”；，推荐阅读搜狗输入法2026获取更多信息
For a small NSFW audio platform run by a solo developer, “true” blackbox DRMs running with TEEs are not a realistic option. Which brings me to the point I actually want to make:，这一点在heLLoword翻译官方下载中也有详细论述